1) Let x and y be events on the same sample space, with P (x) = 0.6 and P (y) = 0.7. Can these two events be disjoint? A) Yes B) No Solution: (B) These two events cannot be disjoint because P(x)+P(y) >1. P(x๊ดy) = P(x)+P(y)-P(x๊ตy). An event is disjoint if P(x๊ตy) = 0. If x and y are disjoint P(x๊ดy) = 0.6+0.7 = 1.3 And Since probability cannot be greater than 1, these two mentioned events cannot be disjoint. 2) Soni has 2 kids and one of them is a girl. What is the probability that the other child is also a girl?You can assume that there are an equal number of males and females in the world. A) 0.5 B) 0.25 C) 0.333 D) 0.75 Solution: (C) The outcomes for two kids can be {BB, BG, GB, GG} Since it is mentioned that one of them is a girl, we can remove the BB option from the sample space. Therefore the sample space has 3 options while only one fits the second condition. Therefore the probability the second child will be a girl too is 1/3. 3) A fair ...
Thank you so much sir
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